N과 M (2)
https://www.acmicpc.net/problem/15650 (opens in a new tab)
풀이
ℹ️
join 함수는 리스트의 요소사이에 특정 문자를 넣어서 문자열로 합치는 함수입니다.
N, M = map(int, input().split())
nums = [i for i in range(1, N + 1)]
def backtrack(curr) :
if len(curr) == M :
print(" ".join(map(str, curr)))
return
for n in nums :
if n not in curr :
curr.append(n)
backtrack(curr)
curr.pop()
backtrack(curr=[])
Java 풀이
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.StringTokenizer;
public class boj_15650 {
static StringBuilder sb = new StringBuilder();
static int n, m;
static boolean[] visit;
static int[] arr;
public static void main(String[] args) throws IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
StringTokenizer st = new StringTokenizer(br.readLine());
n = Integer.parseInt(st.nextToken());
m = Integer.parseInt(st.nextToken());
visit = new boolean[n];
arr = new int[m];
dfs(0,0);
System.out.println(sb);
}
private static void dfs(int depth, int start) {
if (depth == m) {
for (int val : arr) {
sb.append(val).append(" ");
}
sb.append("\n");
return;
}
for (int i = start; i < n; i++) {
if (!visit[i]) {
visit[i] = true;
arr[depth] = i + 1;
dfs(depth + 1, i+1);
visit[i] = false;
}
}
}
}